Polynomials - How To Evaluate GF(256) Element

7 min read Sep 25, 2024
Polynomials - How To Evaluate GF(256) Element

Understanding and Evaluating Elements in GF(256)

The field of Galois, denoted as GF(2^n), plays a pivotal role in numerous applications, particularly in cryptography and error correction codes. One of the most widely used fields is GF(256), which is a finite field with 256 elements. Understanding how to represent and evaluate elements within GF(256) is crucial for implementing cryptographic algorithms or decoding error-corrected data. This article will delve into the fundamental concepts of GF(256) and provide a step-by-step guide on evaluating elements within this field.

Representing Elements in GF(256)

To effectively work with GF(256), we need a clear understanding of how its elements are represented. Unlike the familiar real numbers, GF(256) elements are represented using polynomials over the binary field GF(2). Here's a breakdown:

  • GF(2): This is the simplest finite field containing only two elements: 0 and 1. Operations in GF(2) are defined using modulo-2 arithmetic, meaning that addition and multiplication are performed modulo 2. For example, 1 + 1 = 0 and 1 * 1 = 1.
  • Polynomials over GF(2): Elements in GF(256) are represented as polynomials with coefficients drawn from GF(2). These polynomials have the form: a_n * x^n + a_{n-1} * x^{n-1} + ... + a_1 * x + a_0, where each coefficient a_i is either 0 or 1.

For instance, the polynomial x^3 + x + 1 represents an element in GF(256). The degree of the polynomial (the highest power of x) must be less than 8, as GF(256) contains 256 elements, which can be represented by polynomials of degree up to 7.

Choosing an Irreducible Polynomial

A crucial step in working with GF(256) is selecting an irreducible polynomial. An irreducible polynomial is a polynomial that cannot be factored into smaller polynomials over GF(2). The chosen irreducible polynomial will be used as the modulus for polynomial arithmetic in GF(256).

One commonly used irreducible polynomial for GF(256) is x^8 + x^4 + x^3 + x + 1.

Performing Operations in GF(256)

Arithmetic operations in GF(256) involve polynomial addition, multiplication, and division, all performed modulo the chosen irreducible polynomial. Here's how it works:

  • Addition: Polynomial addition is performed by adding corresponding coefficients, modulo 2. For example, (x^3 + x + 1) + (x^2 + 1) = x^3 + x^2 + x.
  • Multiplication: Polynomial multiplication is done using standard multiplication rules, followed by a reduction step using the chosen irreducible polynomial. The result is the remainder after the polynomial division.
  • Division: Polynomial division is performed using the standard long division algorithm. The remainder is the result of the division operation.

Evaluating Elements in GF(256)

Now, let's dive into the process of evaluating elements in GF(256). Here's a step-by-step approach:

  1. Representation: Represent the element you want to evaluate as a polynomial over GF(2).
  2. Modular Reduction: Apply the chosen irreducible polynomial as the modulus to reduce the polynomial representation of the element. This involves dividing the polynomial by the irreducible polynomial and keeping only the remainder.
  3. Result: The resulting remainder polynomial represents the evaluated element in GF(256).

Example: Evaluating an Element in GF(256)

Let's illustrate this process with an example:

  1. Element: Suppose we want to evaluate the element represented by the polynomial x^5 + x^3 + 1 in GF(256).
  2. Irreducible Polynomial: We will use the irreducible polynomial x^8 + x^4 + x^3 + x + 1.
  3. Modular Reduction: We need to perform polynomial division of x^5 + x^3 + 1 by x^8 + x^4 + x^3 + x + 1:
        0        
x^8 + x^4 + x^3 + x + 1 | x^5 + x^3 + 1
                        - (x^5 + x + 1)
                        ----------------
                                x^3 + x^2
                                - (x^3 + x + 1)
                                ----------------
                                        x^2 + x + 1

The remainder after the division is x^2 + x + 1.

  1. Result: Therefore, the element represented by x^5 + x^3 + 1 in GF(256) evaluates to x^2 + x + 1.

Conclusion

Evaluating elements in GF(256) is a fundamental operation for various applications, particularly in cryptography and coding theory. By understanding how elements are represented as polynomials and performing arithmetic modulo an irreducible polynomial, we can effectively work with this finite field. Mastering these concepts is essential for implementing and understanding algorithms that rely on the properties of GF(256).