Is This Proof That $2^{23} \equiv 1 \bmod{47}$ Correct?

5 min read Sep 25, 2024
Is This Proof That $2^{23} \equiv 1 \bmod{47}$ Correct?

The question of whether $2^{23} \equiv 1 \bmod{47}$ holds true is an interesting one, and the proof you are referring to likely involves Fermat's Little Theorem. This theorem states that for any prime number $p$ and any integer $a$ not divisible by $p$, the following congruence holds:

$a^{p-1} \equiv 1 \pmod{p}$

Let's examine if this proof is correct and explore why.

Applying Fermat's Little Theorem

Since 47 is a prime number and 2 is not divisible by 47, we can directly apply Fermat's Little Theorem:

$2^{47-1} \equiv 1 \pmod{47}$

Simplifying the exponent, we get:

$2^{46} \equiv 1 \pmod{47}$

However, the question asks about $2^{23} \equiv 1 \pmod{47}$. This is where we need to be careful. While Fermat's Little Theorem tells us about the congruence for $2^{46}$, it doesn't directly imply a congruence for $2^{23}$.

The Importance of Congruence Properties

To establish whether $2^{23} \equiv 1 \pmod{47}$ is true, we need to explore congruence properties. Let's consider the following:

If $a \equiv b \pmod{m}$ and $c \equiv d \pmod{m}$, then:

  • Multiplication: $ac \equiv bd \pmod{m}$
  • Exponentiation: $a^n \equiv b^n \pmod{m}$ for any positive integer $n$.

Investigating the Congruence

We know that $2^{46} \equiv 1 \pmod{47}$. Let's see if we can use these congruence properties to get closer to $2^{23}$:

  1. Squaring both sides: Squaring both sides of the congruence $2^{46} \equiv 1 \pmod{47}$ gives us: $(2^{46})^2 \equiv 1^2 \pmod{47}$ Which simplifies to: $2^{92} \equiv 1 \pmod{47}$

  2. Reducing the exponent: Notice that 92 is divisible by 23. We can rewrite the congruence as: $(2^{23})^4 \equiv 1 \pmod{47}$

  3. Applying the Exponentiation Property: We know that if $a^n \equiv b^n \pmod{m}$, then $a \equiv b \pmod{m}$ as long as $n$ is relatively prime to $m$. Since 4 and 47 are relatively prime (they share no common divisors other than 1), we can conclude:

    $2^{23} \equiv 1 \pmod{47}$

Conclusion

Therefore, the proof you are referring to is likely correct and utilizes the properties of congruences and Fermat's Little Theorem to establish that $2^{23} \equiv 1 \pmod{47}$. This demonstrates the power of modular arithmetic and its applications in number theory.

Key Points:

  • Fermat's Little Theorem provides a powerful tool for exploring congruences involving prime numbers.
  • It's crucial to understand the properties of congruences, particularly multiplication and exponentiation, when working with modular arithmetic.
  • While Fermat's Little Theorem doesn't directly give us a congruence for $2^{23}$, we can use its result for $2^{46}$ and congruence properties to derive the desired result.